| 
| A. | P is a constant | B. | P is a character constant |  | C. | P is character type | D. | None of above |  ANS - non
 now p is a contant pointer .
 note --typedef const char *charp;  this is not a valid declaration since typedef doesn't declare an instance of a variable, it declares a type (type alias actually),
 
const is a qualifier you apply to an instance, not a type, so you can use static when you use the type. 
 
| 3. | 
What is x in the following program? #include<stdio.h>
int main()
{
    typedef char (*(*arrfptr[3])())[10];
    arrfptr x;
    return 0;
}
 
 |  | 
ans- c| A. | x is a pointer |  | B. | x is an array of three pointer |  | C. | x is an array of three function pointers |  | D. | Error in x declaration |  
 explanation
 The return value of the function whose function pointer can be any of arrfptr[n]will be a pointer to an array of 10 characters.
 
 The declaration can interpreted as "type of the array to be returned by function(char) (Returning char pointer(*)(function pointer name(*arrfptr)[size of the array of function pointers](3)(parameters)(void))[size of the array which will be returned from the function].
 
 #include<stdio.h>
int main()
{
    enum color{red, green, blue};
    typedef enum color mycolor;
    mycolor m = red;
    printf("%d", m);
    return 0;
}
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